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4(2x-3)=9-3(2+x)
We move all terms to the left:
4(2x-3)-(9-3(2+x))=0
We add all the numbers together, and all the variables
4(2x-3)-(9-3(x+2))=0
We multiply parentheses
8x-(9-3(x+2))-12=0
We calculate terms in parentheses: -(9-3(x+2)), so:We get rid of parentheses
9-3(x+2)
determiningTheFunctionDomain -3(x+2)+9
We multiply parentheses
-3x-6+9
We add all the numbers together, and all the variables
-3x+3
Back to the equation:
-(-3x+3)
8x+3x-3-12=0
We add all the numbers together, and all the variables
11x-15=0
We move all terms containing x to the left, all other terms to the right
11x=15
x=15/11
x=1+4/11
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