4(2f+1)=2(f-13)

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Solution for 4(2f+1)=2(f-13) equation:



4(2f+1)=2(f-13)
We move all terms to the left:
4(2f+1)-(2(f-13))=0
We multiply parentheses
8f-(2(f-13))+4=0
We calculate terms in parentheses: -(2(f-13)), so:
2(f-13)
We multiply parentheses
2f-26
Back to the equation:
-(2f-26)
We get rid of parentheses
8f-2f+26+4=0
We add all the numbers together, and all the variables
6f+30=0
We move all terms containing f to the left, all other terms to the right
6f=-30
f=-30/6
f=-5

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