4(3y-1)=2(y+3)

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Solution for 4(3y-1)=2(y+3) equation: 



4(3y-1)=2(y+3)

We move all terms to the left:

4(3y-1)-(2(y+3))=0

We multiply parentheses

12y-(2(y+3))-4=0



We calculate terms in parentheses: -(2(y+3)), so:

2(y+3)

We multiply parentheses

2y+6

Back to the equation:

-(2y+6)



We get rid of parentheses

12y-2y-6-4=0

We add all the numbers together, and all the variables

10y-10=0

We move all terms containing y to the left, all other terms to the right

10y=10

y=10/10

y=1

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