4-(y+1)=3(y+1)-4(1-y)

Solution for 4-(y+1)=3(y+1)-4(1-y) equation:

4-(y+1)=3(y+1)-4(1-y)

We move all terms to the left:

4-(y+1)-(3(y+1)-4(1-y))=0

We add all the numbers together, and all the variables

-(y+1)-(3(y+1)-4(-1y+1))+4=0

We get rid of parentheses

-y-(3(y+1)-4(-1y+1))-1+4=0


We calculate terms in parentheses: -(3(y+1)-4(-1y+1)), so:

3(y+1)-4(-1y+1)

We multiply parentheses

3y+4y+3-4

We add all the numbers together, and all the variables

7y-1

Back to the equation:

-(7y-1)


We add all the numbers together, and all the variables

-1y-(7y-1)+3=0

We get rid of parentheses

-1y-7y+1+3=0

We add all the numbers together, and all the variables

-8y+4=0

We move all terms containing y to the left, all other terms to the right

-8y=-4

y=-4/-8

y=1/2