(2x+3)x=629

Solution for (2x+3)x=629 equation:

(2x+3)x=629

We move all terms to the left:

(2x+3)x-(629)=0

We multiply parentheses

2x^2+3x-629=0

a = 2; b = 3; c = -629;
Δ = b2-4ac
Δ = 32-4·2·(-629)
Δ = 5041
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5041}=71$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-71}{2*2}=\frac{-74}{4}
=-18+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+71}{2*2}=\frac{68}{4}
=17
$