4(2c)+2=(c-5)

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Solution for 4(2c)+2=(c-5) equation: 



4(2c)+2=(c-5)

We move all terms to the left:

4(2c)+2-((c-5))=0



We calculate terms in parentheses: -((c-5)), so:

(c-5)

We get rid of parentheses

c-5

Back to the equation:

-(c-5)



We get rid of parentheses

42c-c+5+2=0

We add all the numbers together, and all the variables

41c+7=0

We move all terms containing c to the left, all other terms to the right

41c=-7

c=-7/41

c=-7/41

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