4(2u-3)+u=15

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Solution for 4(2u-3)+u=15 equation:



4(2u-3)+u=15
We move all terms to the left:
4(2u-3)+u-(15)=0
We add all the numbers together, and all the variables
u+4(2u-3)-15=0
We multiply parentheses
u+8u-12-15=0
We add all the numbers together, and all the variables
9u-27=0
We move all terms containing u to the left, all other terms to the right
9u=27
u=27/9
u=3

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