3(t+2)-t=10

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Solution for 3(t+2)-t=10 equation: 



3(t+2)-t=10

We move all terms to the left:

3(t+2)-t-(10)=0

We add all the numbers together, and all the variables

-1t+3(t+2)-10=0

We multiply parentheses

-1t+3t+6-10=0

We add all the numbers together, and all the variables

2t-4=0

We move all terms containing t to the left, all other terms to the right

2t=4

t=4/2

t=2

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