4(t-3)+4=(2t-4)

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Solution for 4(t-3)+4=(2t-4) equation: 



4(t-3)+4=(2t-4)

We move all terms to the left:

4(t-3)+4-((2t-4))=0

We multiply parentheses

4t-((2t-4))-12+4=0



We calculate terms in parentheses: -((2t-4)), so:

(2t-4)

We get rid of parentheses

2t-4

Back to the equation:

-(2t-4)



We add all the numbers together, and all the variables

4t-(2t-4)-8=0

We get rid of parentheses

4t-2t+4-8=0

We add all the numbers together, and all the variables

2t-4=0

We move all terms containing t to the left, all other terms to the right

2t=4

t=4/2

t=2

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