4(1+b)=8(b+1)

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Solution for 4(1+b)=8(b+1) equation: 



4(1+b)=8(b+1)

We move all terms to the left:

4(1+b)-(8(b+1))=0

We add all the numbers together, and all the variables

4(b+1)-(8(b+1))=0

We multiply parentheses

4b-(8(b+1))+4=0



We calculate terms in parentheses: -(8(b+1)), so:

8(b+1)

We multiply parentheses

8b+8

Back to the equation:

-(8b+8)



We get rid of parentheses

4b-8b-8+4=0

We add all the numbers together, and all the variables

-4b-4=0

We move all terms containing b to the left, all other terms to the right

-4b=4

b=4/-4

b=-1

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