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10-2(2x-4)=2(3x+4)
We move all terms to the left:
10-2(2x-4)-(2(3x+4))=0
We multiply parentheses
-4x-(2(3x+4))+8+10=0
We calculate terms in parentheses: -(2(3x+4)), so:We add all the numbers together, and all the variables
2(3x+4)
We multiply parentheses
6x+8
Back to the equation:
-(6x+8)
-4x-(6x+8)+18=0
We get rid of parentheses
-4x-6x-8+18=0
We add all the numbers together, and all the variables
-10x+10=0
We move all terms containing x to the left, all other terms to the right
-10x=-10
x=-10/-10
x=1
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