3(x-2)+5(3-x)=16

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Solution for 3(x-2)+5(3-x)=16 equation: 



3(x-2)+5(3-x)=16

We move all terms to the left:

3(x-2)+5(3-x)-(16)=0

We add all the numbers together, and all the variables

3(x-2)+5(-1x+3)-16=0

We multiply parentheses

3x-5x-6+15-16=0

We add all the numbers together, and all the variables

-2x-7=0

We move all terms containing x to the left, all other terms to the right

-2x=7

x=7/-2

x=-3+1/2

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