5x+3-(7x-2-(4x+8))=x+19

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Solution for 5x+3-(7x-2-(4x+8))=x+19 equation: 



5x+3-(7x-2-(4x+8))=x+19

We move all terms to the left:

5x+3-(7x-2-(4x+8))-(x+19)=0

We get rid of parentheses

5x-(7x-2-(4x+8))-x-19+3=0



We calculate terms in parentheses: -(7x-2-(4x+8)), so:

7x-2-(4x+8)

determiningTheFunctionDomain
7x-(4x+8)-2

We get rid of parentheses

7x-4x-8-2

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

4x-(3x-10)-16=0

We get rid of parentheses

4x-3x+10-16=0

We add all the numbers together, and all the variables

x-6=0

We move all terms containing x to the left, all other terms to the right

x=6

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