-5(-3u+7)-3u=6(u-3)-2

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Solution for -5(-3u+7)-3u=6(u-3)-2 equation: 



-5(-3u+7)-3u=6(u-3)-2

We move all terms to the left:

-5(-3u+7)-3u-(6(u-3)-2)=0

We add all the numbers together, and all the variables

-3u-5(-3u+7)-(6(u-3)-2)=0

We multiply parentheses

-3u+15u-(6(u-3)-2)-35=0



We calculate terms in parentheses: -(6(u-3)-2), so:

6(u-3)-2

We multiply parentheses

6u-18-2

We add all the numbers together, and all the variables

6u-20

Back to the equation:

-(6u-20)



We add all the numbers together, and all the variables

12u-(6u-20)-35=0

We get rid of parentheses

12u-6u+20-35=0

We add all the numbers together, and all the variables

6u-15=0

We move all terms containing u to the left, all other terms to the right

6u=15

u=15/6

u=2+1/2

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