3y+7(y+5)=35

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Solution for 3y+7(y+5)=35 equation: 



3y+7(y+5)=35

We move all terms to the left:

3y+7(y+5)-(35)=0

We multiply parentheses

3y+7y+35-35=0

We add all the numbers together, and all the variables

10y=0

y=0/10

y=0

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