2n-4-(3-n)=11

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Solution for 2n-4-(3-n)=11 equation: 



2n-4-(3-n)=11

We move all terms to the left:

2n-4-(3-n)-(11)=0

We add all the numbers together, and all the variables

2n-(-1n+3)-4-11=0

We add all the numbers together, and all the variables

2n-(-1n+3)-15=0

We get rid of parentheses

2n+1n-3-15=0

We add all the numbers together, and all the variables

3n-18=0

We move all terms containing n to the left, all other terms to the right

3n=18

n=18/3

n=6

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