0.15(y-0.2)=2-0-0.5(1-y)y=

Solution for 0.15(y-0.2)=2-0-0.5(1-y)y= equation:

0.15(y-0.2)=2-0-0.5(1-y)y=

We move all terms to the left:

0.15(y-0.2)-(2-0-0.5(1-y)y)=0

We add all the numbers together, and all the variables

0.15(y-0.2)-(2-0-0.5(-1y+1)y)=0

We multiply parentheses

0.15y-(2-0-0.5(-1y+1)y)-0.03=0


We calculate terms in parentheses: -(2-0-0.5(-1y+1)y), so:

2-0-0.5(-1y+1)y

determiningTheFunctionDomain
-0.5(-1y+1)y+2-0

We add all the numbers together, and all the variables

-0.5(-1y+1)y+2

We multiply parentheses

-0y^2-0y+2

We add all the numbers together, and all the variables

-1y^2-1y+2

Back to the equation:

-(-1y^2-1y+2)


We get rid of parentheses

1y^2+1y+0.15y-2-0.03=0

We add all the numbers together, and all the variables

y^2+1.15y-2.03=0

a = 1; b = 1.15; c = -2.03;
Δ = b2-4ac
Δ = 1.152-4·1·(-2.03)
Δ = 9.4425
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.15)-\sqrt{9.4425}}{2*1}=\frac{-1.15-\sqrt{9.4425}}{2}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.15)+\sqrt{9.4425}}{2*1}=\frac{-1.15+\sqrt{9.4425}}{2}
$