3x-2(4x-5)=3(x-2)

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Solution for 3x-2(4x-5)=3(x-2) equation: 



3x-2(4x-5)=3(x-2)

We move all terms to the left:

3x-2(4x-5)-(3(x-2))=0

We multiply parentheses

3x-8x-(3(x-2))+10=0



We calculate terms in parentheses: -(3(x-2)), so:

3(x-2)

We multiply parentheses

3x-6

Back to the equation:

-(3x-6)



We add all the numbers together, and all the variables

-5x-(3x-6)+10=0

We get rid of parentheses

-5x-3x+6+10=0

We add all the numbers together, and all the variables

-8x+16=0

We move all terms containing x to the left, all other terms to the right

-8x=-16

x=-16/-8

x=+2

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