4(2y-6)+2=20

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Solution for 4(2y-6)+2=20 equation: 



4(2y-6)+2=20

We move all terms to the left:

4(2y-6)+2-(20)=0

We add all the numbers together, and all the variables

4(2y-6)-18=0

We multiply parentheses

8y-24-18=0

We add all the numbers together, and all the variables

8y-42=0

We move all terms containing y to the left, all other terms to the right

8y=42

y=42/8

y=5+1/4

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