9+3b+2(b-1)=67

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Solution for 9+3b+2(b-1)=67 equation: 



9+3b+2(b-1)=67

We move all terms to the left:

9+3b+2(b-1)-(67)=0

We add all the numbers together, and all the variables

3b+2(b-1)-58=0

We multiply parentheses

3b+2b-2-58=0

We add all the numbers together, and all the variables

5b-60=0

We move all terms containing b to the left, all other terms to the right

5b=60

b=60/5

b=12

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