3x(2x-5)-4(2x+5)=(2x+5)(3x-4)

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Solution for 3x(2x-5)-4(2x+5)=(2x+5)(3x-4) equation: 



3x(2x-5)-4(2x+5)=(2x+5)(3x-4)

We move all terms to the left:

3x(2x-5)-4(2x+5)-((2x+5)(3x-4))=0

We multiply parentheses

6x^2-15x-8x-((2x+5)(3x-4))-20=0

We multiply parentheses ..

6x^2-((+6x^2-8x+15x-20))-15x-8x-20=0



We calculate terms in parentheses: -((+6x^2-8x+15x-20)), so:

(+6x^2-8x+15x-20)

We get rid of parentheses

6x^2-8x+15x-20

We add all the numbers together, and all the variables

6x^2+7x-20

Back to the equation:

-(6x^2+7x-20)



We add all the numbers together, and all the variables

6x^2-23x-(6x^2+7x-20)-20=0

We get rid of parentheses

6x^2-6x^2-23x-7x+20-20=0

We add all the numbers together, and all the variables

-30x=0

x=0/-30

x=0

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