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2x+3x/5x=1
We move all terms to the left:
2x+3x/5x-(1)=0
Domain of the equation: 5x!=0We multiply all the terms by the denominator
x!=0/5
x!=0
x∈R
2x*5x+3x-1*5x=0
We add all the numbers together, and all the variables
3x+2x*5x-1*5x=0
Wy multiply elements
10x^2+3x-5x=0
We add all the numbers together, and all the variables
10x^2-2x=0
a = 10; b = -2; c = 0;
Δ = b2-4ac
Δ = -22-4·10·0
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2}{2*10}=\frac{0}{20} =0 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2}{2*10}=\frac{4}{20} =1/5 $
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