3x+4(4x+5)=33

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Solution for 3x+4(4x+5)=33 equation: 



3x+4(4x+5)=33

We move all terms to the left:

3x+4(4x+5)-(33)=0

We multiply parentheses

3x+16x+20-33=0

We add all the numbers together, and all the variables

19x-13=0

We move all terms containing x to the left, all other terms to the right

19x=13

x=13/19

x=13/19

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