3x=4(4x+5)=33

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Solution for 3x=4(4x+5)=33 equation: 



3x=4(4x+5)=33

We move all terms to the left:

3x-(4(4x+5))=0



We calculate terms in parentheses: -(4(4x+5)), so:

4(4x+5)

We multiply parentheses

16x+20

Back to the equation:

-(16x+20)



We get rid of parentheses

3x-16x-20=0

We add all the numbers together, and all the variables

-13x-20=0

We move all terms containing x to the left, all other terms to the right

-13x=20

x=20/-13

x=-1+7/13

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