3/4(x-12)=1/4(x+20)

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Solution for 3/4(x-12)=1/4(x+20) equation: 



3/4(x-12)=1/4(x+20)

We move all terms to the left:

3/4(x-12)-(1/4(x+20))=0



Domain of the equation: 4(x-12)!=0

x∈R





Domain of the equation: 4(x+20))!=0

x∈R



We calculate fractions


(12xx/(4(x-12)*4(x+20)))+(-4xx/(4(x-12)*4(x+20)))=0



We calculate terms in parentheses: +(12xx/(4(x-12)*4(x+20))), so:

12xx/(4(x-12)*4(x+20))

We multiply all the terms by the denominator


12xx

Back to the equation:

+(12xx)





We calculate terms in parentheses: +(-4xx/(4(x-12)*4(x+20))), so:

-4xx/(4(x-12)*4(x+20))

We multiply all the terms by the denominator


-4xx

Back to the equation:

+(-4xx)



We get rid of parentheses

12xx-4xx=0

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