3/4(-8x+12)-2=-3(2x+1)

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Solution for 3/4(-8x+12)-2=-3(2x+1) equation: 



3/4(-8x+12)-2=-3(2x+1)

We move all terms to the left:

3/4(-8x+12)-2-(-3(2x+1))=0



Domain of the equation: 4(-8x+12)!=0

x∈R



We multiply all the terms by the denominator


-((-3(2x+1)))*4(-8x+12)-2*4(-8x+12)+3=0



We calculate terms in parentheses: -((-3(2x+1)))*4(-8x+12), so:

(-3(2x+1)))*4(-8x+12

We add all the numbers together, and all the variables

-8x+(-3(2x+1)))*4(+12

Back to the equation:

-(-8x+(-3(2x+1)))*4(+12)



We add all the numbers together, and all the variables

-(-8x+(-3(2x+1)))*412-2*4(-8x+12)+3=0

Wy multiply elements

-(-8x+(-3(2x+1)))*412-8x(-+3=0

We use the square of the difference formula

-(-8x+(-3(2x+1)))*412-8x(-3=0

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