3x+4(4+3)=30x-2(11-3x)

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Solution for 3x+4(4+3)=30x-2(11-3x) equation: 



3x+4(4+3)=30x-2(11-3x)

We move all terms to the left:

3x+4(4+3)-(30x-2(11-3x))=0

We add all the numbers together, and all the variables

3x-(30x-2(-3x+11))+47=0



We calculate terms in parentheses: -(30x-2(-3x+11)), so:

30x-2(-3x+11)

We multiply parentheses

30x+6x-22

We add all the numbers together, and all the variables

36x-22

Back to the equation:

-(36x-22)



We get rid of parentheses

3x-36x+22+47=0

We add all the numbers together, and all the variables

-33x+69=0

We move all terms containing x to the left, all other terms to the right

-33x=-69

x=-69/-33

x=2+1/11

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