4(b-6)+19=4b-5

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Solution for 4(b-6)+19=4b-5 equation: 



4(b-6)+19=4b-5

We move all terms to the left:

4(b-6)+19-(4b-5)=0

We multiply parentheses

4b-(4b-5)-24+19=0

We get rid of parentheses

4b-4b+5-24+19=0

We add all the numbers together, and all the variables

=0

b=0/1

b=0

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