4n-2(n-5)=4(3n-5)

Solution for 4n-2(n-5)=4(3n-5) equation:

4n-2(n-5)=4(3n-5)

We move all terms to the left:

4n-2(n-5)-(4(3n-5))=0

We multiply parentheses

4n-2n-(4(3n-5))+10=0


We calculate terms in parentheses: -(4(3n-5)), so:

4(3n-5)

We multiply parentheses

12n-20

Back to the equation:

-(12n-20)


We add all the numbers together, and all the variables

2n-(12n-20)+10=0

We get rid of parentheses

2n-12n+20+10=0

We add all the numbers together, and all the variables

-10n+30=0

We move all terms containing n to the left, all other terms to the right

-10n=-30

n=-30/-10

n=+3