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(3(3x+1))/4=2x+1
We move all terms to the left:
(3(3x+1))/4-(2x+1)=0
We get rid of parentheses
(3(3x+1))/4-2x-1=0
We multiply all the terms by the denominator
(3(3x+1))-2x*4-1*4=0
We calculate terms in parentheses: +(3(3x+1)), so:We add all the numbers together, and all the variables
3(3x+1)
We multiply parentheses
9x+3
Back to the equation:
+(9x+3)
(9x+3)-2x*4-4=0
Wy multiply elements
(9x+3)-8x-4=0
We get rid of parentheses
9x-8x+3-4=0
We add all the numbers together, and all the variables
x-1=0
We move all terms containing x to the left, all other terms to the right
x=1
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