-2/3(12c-9)+14c=6c+6

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Solution for -2/3(12c-9)+14c=6c+6 equation: 



-2/3(12c-9)+14c=6c+6

We move all terms to the left:

-2/3(12c-9)+14c-(6c+6)=0



Domain of the equation: 3(12c-9)!=0

c∈R



We add all the numbers together, and all the variables

14c-2/3(12c-9)-(6c+6)=0

We get rid of parentheses

14c-2/3(12c-9)-6c-6=0

We multiply all the terms by the denominator


14c*3(12c-9)-6c*3(12c-9)-6*3(12c-9)-2=0

Wy multiply elements

42c^2(1-18c^2(1-18c(1-2=0

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