3i+9i+21=3(i+7)

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Solution for 3i+9i+21=3(i+7) equation: 



3i+9i+21=3(i+7)

We move all terms to the left:

3i+9i+21-(3(i+7))=0

We add all the numbers together, and all the variables

12i-(3(i+7))+21=0



We calculate terms in parentheses: -(3(i+7)), so:

3(i+7)

We multiply parentheses

3i+21

Back to the equation:

-(3i+21)



We get rid of parentheses

12i-3i-21+21=0

We add all the numbers together, and all the variables

9i=0

i=0/9

i=0

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