3(-1)-8=4(1+i)+5

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Solution for 3(-1)-8=4(1+i)+5 equation: 



3(-1)-8=4(1+i)+5

We move all terms to the left:

3(-1)-8-(4(1+i)+5)=0

We add all the numbers together, and all the variables

-(4(i+1)+5)-8+3(-1)=0

We add all the numbers together, and all the variables

-(4(i+1)+5)-11=0



We calculate terms in parentheses: -(4(i+1)+5), so:

4(i+1)+5

We multiply parentheses

4i+4+5

We add all the numbers together, and all the variables

4i+9

Back to the equation:

-(4i+9)



We get rid of parentheses

-4i-9-11=0

We add all the numbers together, and all the variables

-4i-20=0

We move all terms containing i to the left, all other terms to the right

-4i=20

i=20/-4

i=-5

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