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(2x-16)(3x+4)=180
We move all terms to the left:
(2x-16)(3x+4)-(180)=0
We multiply parentheses ..
(+6x^2+8x-48x-64)-180=0
We get rid of parentheses
6x^2+8x-48x-64-180=0
We add all the numbers together, and all the variables
6x^2-40x-244=0
a = 6; b = -40; c = -244;
Δ = b2-4ac
Δ = -402-4·6·(-244)
Δ = 7456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7456}=\sqrt{16*466}=\sqrt{16}*\sqrt{466}=4\sqrt{466}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-4\sqrt{466}}{2*6}=\frac{40-4\sqrt{466}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+4\sqrt{466}}{2*6}=\frac{40+4\sqrt{466}}{12} $
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