3(i-1)-8=4(1+i)+5

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Solution for 3(i-1)-8=4(1+i)+5 equation: 



3(i-1)-8=4(1+i)+5

We move all terms to the left:

3(i-1)-8-(4(1+i)+5)=0

We add all the numbers together, and all the variables

3(i-1)-(4(i+1)+5)-8=0

We multiply parentheses

3i-(4(i+1)+5)-3-8=0



We calculate terms in parentheses: -(4(i+1)+5), so:

4(i+1)+5

We multiply parentheses

4i+4+5

We add all the numbers together, and all the variables

4i+9

Back to the equation:

-(4i+9)



We add all the numbers together, and all the variables

3i-(4i+9)-11=0

We get rid of parentheses

3i-4i-9-11=0

We add all the numbers together, and all the variables

-1i-20=0

We move all terms containing i to the left, all other terms to the right

-i=20

i=20/-1

i=-20

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