-3=((x+1)-(x-5))/(-3-x)

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Solution for -3=((x+1)-(x-5))/(-3-x) equation: 



-3=((x+1)-(x-5))/(-3-x)

We move all terms to the left:

-3-(((x+1)-(x-5))/(-3-x))=0



Domain of the equation: (-3-x))!=0

We move all terms containing x to the left, all other terms to the right

-x)!=3

x!=3/1

x!=3

x∈R



We add all the numbers together, and all the variables

-(((x+1)-(x-5))/(-1x-3))-3=0

We multiply all the terms by the denominator


-(((x+1)-(x-5))-3*(-1x-3))=0



We calculate terms in parentheses: -(((x+1)-(x-5))-3*(-1x-3)), so:

((x+1)-(x-5))-3*(-1x-3)

We multiply parentheses

((x+1)-(x-5))+3x+9



We calculate terms in parentheses: +((x+1)-(x-5)), so:

(x+1)-(x-5)

We get rid of parentheses

x-x+1+5

We add all the numbers together, and all the variables

6

Back to the equation:

+(6)



We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We get rid of parentheses

-3x-15=0

We move all terms containing x to the left, all other terms to the right

-3x=15

x=15/-3

x=-5

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