6(2y+5)=2(y+10)

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Solution for 6(2y+5)=2(y+10) equation: 



6(2y+5)=2(y+10)

We move all terms to the left:

6(2y+5)-(2(y+10))=0

We multiply parentheses

12y-(2(y+10))+30=0



We calculate terms in parentheses: -(2(y+10)), so:

2(y+10)

We multiply parentheses

2y+20

Back to the equation:

-(2y+20)



We get rid of parentheses

12y-2y-20+30=0

We add all the numbers together, and all the variables

10y+10=0

We move all terms containing y to the left, all other terms to the right

10y=-10

y=-10/10

y=-1

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