3a-2(a-5)=2(a+3)-8

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Solution for 3a-2(a-5)=2(a+3)-8 equation: 



3a-2(a-5)=2(a+3)-8

We move all terms to the left:

3a-2(a-5)-(2(a+3)-8)=0

We multiply parentheses

3a-2a-(2(a+3)-8)+10=0



We calculate terms in parentheses: -(2(a+3)-8), so:

2(a+3)-8

We multiply parentheses

2a+6-8

We add all the numbers together, and all the variables

2a-2

Back to the equation:

-(2a-2)



We add all the numbers together, and all the variables

a-(2a-2)+10=0

We get rid of parentheses

a-2a+2+10=0

We add all the numbers together, and all the variables

-1a+12=0

We move all terms containing a to the left, all other terms to the right

-a=-12

a=-12/-1

a=+12

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