2m+(m+2)=20-(2m-5)

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Solution for 2m+(m+2)=20-(2m-5) equation: 



2m+(m+2)=20-(2m-5)

We move all terms to the left:

2m+(m+2)-(20-(2m-5))=0

We get rid of parentheses

2m+m-(20-(2m-5))+2=0



We calculate terms in parentheses: -(20-(2m-5)), so:

20-(2m-5)

determiningTheFunctionDomain
-(2m-5)+20

We get rid of parentheses

-2m+5+20

We add all the numbers together, and all the variables

-2m+25

Back to the equation:

-(-2m+25)



We add all the numbers together, and all the variables

3m-(-2m+25)+2=0

We get rid of parentheses

3m+2m-25+2=0

We add all the numbers together, and all the variables

5m-23=0

We move all terms containing m to the left, all other terms to the right

5m=23

m=23/5

m=4+3/5

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