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-(6/5)k=12
We move all terms to the left:
-(6/5)k-(12)=0
Domain of the equation: 5)k!=0We add all the numbers together, and all the variables
k!=0/1
k!=0
k∈R
-(+6/5)k-12=0
We multiply parentheses
-6k^2-12=0
a = -6; b = 0; c = -12;
Δ = b2-4ac
Δ = 02-4·(-6)·(-12)
Δ = -288
Delta is less than zero, so there is no solution for the equation
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