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-2/15+1/6x=-4/5.x
We move all terms to the left:
-2/15+1/6x-(-4/5.x)=0
Domain of the equation: 6x!=0
x!=0/6
x!=0
x∈R
Domain of the equation: 5.x)!=0We get rid of parentheses
x!=0/1
x!=0
x∈R
1/6x+4/5.x-2/15=0
We calculate fractions
(-300x^2)/450x^2+75x/450x^2+360x/450x^2=0
We multiply all the terms by the denominator
(-300x^2)+75x+360x=0
We add all the numbers together, and all the variables
(-300x^2)+435x=0
We get rid of parentheses
-300x^2+435x=0
a = -300; b = 435; c = 0;
Δ = b2-4ac
Δ = 4352-4·(-300)·0
Δ = 189225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{189225}=435$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(435)-435}{2*-300}=\frac{-870}{-600} =1+9/20 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(435)+435}{2*-300}=\frac{0}{-600} =0 $
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