37-4(3-n)=-5(n+3)+9

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Solution for 37-4(3-n)=-5(n+3)+9 equation: 



37-4(3-n)=-5(n+3)+9

We move all terms to the left:

37-4(3-n)-(-5(n+3)+9)=0

We add all the numbers together, and all the variables

-4(-1n+3)-(-5(n+3)+9)+37=0

We multiply parentheses

4n-(-5(n+3)+9)-12+37=0



We calculate terms in parentheses: -(-5(n+3)+9), so:

-5(n+3)+9

We multiply parentheses

-5n-15+9

We add all the numbers together, and all the variables

-5n-6

Back to the equation:

-(-5n-6)



We add all the numbers together, and all the variables

4n-(-5n-6)+25=0

We get rid of parentheses

4n+5n+6+25=0

We add all the numbers together, and all the variables

9n+31=0

We move all terms containing n to the left, all other terms to the right

9n=-31

n=-31/9

n=-3+4/9

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