720x(1-15x)=0

Solution for 720x(1-15x)=0 equation:

720x(1-15x)=0

We add all the numbers together, and all the variables

720x(-15x+1)=0

We multiply parentheses

-10800x^2+720x=0

a = -10800; b = 720; c = 0;
Δ = b2-4ac
Δ = 7202-4·(-10800)·0
Δ = 518400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{518400}=720$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(720)-720}{2*-10800}=\frac{-1440}{-21600}
=1/15
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(720)+720}{2*-10800}=\frac{0}{-21600}
=0
$