6x+4=4((3/2)x+1)

Solution for 6x+4=4((3/2)x+1) equation:

6x+4=4((3/2)x+1)

We move all terms to the left:

6x+4-(4((3/2)x+1))=0


Domain of the equation: 2)x+1))!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

6x-(4((+3/2)x+1))+4=0

We multiply all the terms by the denominator


6x*2)x+1))-(4((+4*2)x+1))+3=0

We add all the numbers together, and all the variables

6x*2)x+1))-(4(8x+1))+3=0

Wy multiply elements

12x^2=0

a = 12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·12·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{24}=0$