2u-2+2(7u+3)=-2(u+6)

Solution for 2u-2+2(7u+3)=-2(u+6) equation:

2u-2+2(7u+3)=-2(u+6)

We move all terms to the left:

2u-2+2(7u+3)-(-2(u+6))=0

We multiply parentheses

2u+14u-(-2(u+6))+6-2=0


We calculate terms in parentheses: -(-2(u+6)), so:

-2(u+6)

We multiply parentheses

-2u-12

Back to the equation:

-(-2u-12)


We add all the numbers together, and all the variables

16u-(-2u-12)+4=0

We get rid of parentheses

16u+2u+12+4=0

We add all the numbers together, and all the variables

18u+16=0

We move all terms containing u to the left, all other terms to the right

18u=-16

u=-16/18

u=-8/9