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2y*y=800
We move all terms to the left:
2y*y-(800)=0
Wy multiply elements
2y^2-800=0
a = 2; b = 0; c = -800;
Δ = b2-4ac
Δ = 02-4·2·(-800)
Δ = 6400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{6400}=80$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-80}{2*2}=\frac{-80}{4} =-20 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+80}{2*2}=\frac{80}{4} =20 $
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