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36n^2-5n-26=0
a = 36; b = -5; c = -26;
Δ = b2-4ac
Δ = -52-4·36·(-26)
Δ = 3769
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{3769}}{2*36}=\frac{5-\sqrt{3769}}{72} $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{3769}}{2*36}=\frac{5+\sqrt{3769}}{72} $
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