36-(3c+4)=2(c+7+c)

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Solution for 36-(3c+4)=2(c+7+c) equation: 



36-(3c+4)=2(c+7+c)

We move all terms to the left:

36-(3c+4)-(2(c+7+c))=0

We add all the numbers together, and all the variables

-(3c+4)-(2(2c+7))+36=0

We get rid of parentheses

-3c-(2(2c+7))-4+36=0



We calculate terms in parentheses: -(2(2c+7)), so:

2(2c+7)

We multiply parentheses

4c+14

Back to the equation:

-(4c+14)



We add all the numbers together, and all the variables

-3c-(4c+14)+32=0

We get rid of parentheses

-3c-4c-14+32=0

We add all the numbers together, and all the variables

-7c+18=0

We move all terms containing c to the left, all other terms to the right

-7c=-18

c=-18/-7

c=2+4/7

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