2(n+6)=40-6(n-2)

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Solution for 2(n+6)=40-6(n-2) equation: 



2(n+6)=40-6(n-2)

We move all terms to the left:

2(n+6)-(40-6(n-2))=0

We multiply parentheses

2n-(40-6(n-2))+12=0



We calculate terms in parentheses: -(40-6(n-2)), so:

40-6(n-2)

determiningTheFunctionDomain
-6(n-2)+40

We multiply parentheses

-6n+12+40

We add all the numbers together, and all the variables

-6n+52

Back to the equation:

-(-6n+52)



We get rid of parentheses

2n+6n-52+12=0

We add all the numbers together, and all the variables

8n-40=0

We move all terms containing n to the left, all other terms to the right

8n=40

n=40/8

n=5

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