29-1(2c+3)=2(1c+3)+1c

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Solution for 29-1(2c+3)=2(1c+3)+1c equation: 



29-1(2c+3)=2(1c+3)+1c

We move all terms to the left:

29-1(2c+3)-(2(1c+3)+1c)=0

We add all the numbers together, and all the variables

-1(2c+3)-(2(c+3)+1c)+29=0



We calculate terms in parentheses: -(2(c+3)+1c), so:

2(c+3)+1c

We add all the numbers together, and all the variables

c+2(c+3)

We multiply parentheses

c+2c+6

We add all the numbers together, and all the variables

3c+6

Back to the equation:

-(3c+6)



We get rid of parentheses

-1(2c+3)-3c-6+29=0

We add all the numbers together, and all the variables

-3c-1(2c+3)+23=0

We move all terms containing c to the left, all other terms to the right

-3c-1(2c+3)=-23

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